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Lessons · Engineering · Pascal's principle and the hydraulic jack

Pascal's principle: the same pressure everywhere, so area multiplies force

Pressure in a confined fluid is the same at every point, so F_1 / A_1 = F_2 / A_2. A small push on a small piston becomes a big push on a big one.

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What it is for

A two-tonne car goes up on a jack a person works by hand. Nothing is free: the small piston travels many times farther than the big one. Sizing the ram and the pump comes down to this one ratio.

How to think about it

Find the pressure from the side you know, force over area. Apply that same pressure to the other area. If the problem gives diameters, square them: doubling a diameter quadruples the area and the force.

Worked example

Pressure is the same everywhere in a confined fluid, so F_1 / A_1 = F_2 / A_2
The principle, written as the equation you will use.
Jack: small piston 4 cm², large piston 100 cm², effort 80 N
The setup.
p = 80 / 4 = 20 N/cm²; F_2 = 20 × 100 = 2000 N
Pressure from the small side, force on the large side.
The trade: the small piston moves 25 times as far as the large one
Force is multiplied by 25 and distance divided by 25. Work is not multiplied at all.

Your turn

Areas 3 cm² and 60 cm², effort 50 N. Write the lift.

F_2 = 50 × 60 /  = 1000 N

The trap

Using diameters as though they were areas. A ram twice the diameter has four times the area; the multiplication is by the square of the diameter ratio, not the ratio itself.

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